Question

The task is to send an XML object from Channel-A to Channel-B

<MyMessage>
<ID>42</ID>
<hl7v2>
    MSH|^~\&|LAB|....
    PID|1|....
</hl7v2>
</MyMessage>

The steps of the channel communication:

• in the Channel-B’s source transformer, extract the HL7v2 contents
• OVERWRITE the current msg object in Channel-B with the extracted contents
• continue in the other Channel-B source transformers and expecting to reference msg['PID']['PID.5'] as normal.

The good news is that I can extract the HL7v2 ‘payload’ into a variable. The problem or difficulty is resetting the msg object, or any other object to be able to reference the HL7 properties as expected.

When I create a new variable with the SerializerFactory.getHL7Serializer, it wraps with the tags <HL7Message>.

channelMap.put('MessageID', msg['ID']); //successful
channelMap.put('v2payload',msg['HL7v2']); //also looks good

var v2Msg = SerializerFactory.getHL7Serializer(false,false,true).toXML(msg['HL7v2']);

channelMap.put('v2Msg', v2Msg );

link to full size image

Question: Do you have any suggestions on how to overwrite the msg object?

How can I start referencing the msg as such:

msg['PID']['PID.5']

Current Conditions

• the receiving channel’s input type is XML
• the need is to take extract all the properties from that XML object; ID is a database PK to be used later in the destination.

Answer 1

I’m sorry my original answer was bogged down with the peculiarities of my own scenario. I have reworked and tested to ensure that this works in your scenario.

Sending Channel – wraps the raw hl7 into your xml structure, and forwards to a channel called ReceiveXML. I have coded this in the Source Transformer, but you should code it where it works for you.

var wrappedHL7 = <MyMessage><ID>123</ID>
                      <hl7v2>{messageObject.getRawData()}</hl7v2>
                 </MyMessage>;

router.routeMessage("ReceiveXML", wrappedHL7);

Receiving Channel – extracts the hl7 from the xml, converts it to xml, and assigns back to the msg object. I have coded this in the source Filter – hence “return true;”

msg = new XML(SerializerFactory.getHL7Serializer(false,false,true).toXML(msg['hl7v2'].toString()));
return true;