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Home/ Questions/Q 135095
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Asked: May 11, 20262026-05-11T06:43:55+00:00 2026-05-11T06:43:55+00:00

The testit() method is a closure. aString has fallen out of scope but testit()

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The testit() method is a closure. aString has fallen out of scope but testit() can still execute on it. testit2() is using a variable that hasn’t fallen out of scope (mystring) but which was also not been passed into testit2(). Is testit2() considered a closure?

string mystring = 'hello world'; Action testit = new Action(delegate { string aString = 'in anon method'; Debug.WriteLine(aString); }); testit();  //capture mystring.  Is this still a closure? Action testit2 = new Action(delegate { Debug.WriteLine(mystring); }); //mystring is still in scope testit2(); 

In the second example, mystring can be updated outside of the method and those changes will be reflected in testit2(). This doesn’t behave like a normal method, which would only be able to capture mystring as a parameter.

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  1. 2026-05-11T06:43:56+00:00Added an answer on May 11, 2026 at 6:43 am

    Both examples are anonymous functions. The second of which use a closure in order to capture the local variables. The scope lifetime of the variable with respect to the anonymous function does not affect whether or not a closure is created to use it. As long as the variable is defined outside a anonymous function and used within, a closure will be created.

    The first anonymous function uses no local state, therefore does not need a closure. It should compile down to a static method.

    This is necessary because the anonymous function can live past the lifetime of the current function. Therefore all locals used in a anonymous function must be captured in order to execute the delegate at a later time.

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