Question

The thing is i’m creating a honeycomb app and i can’t switch between fragments . Here’s my main code :

public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);
    list = (ListView)findViewById(R.id.list);
    A = new FragmentA();
    B = new FragmentB();
    adapter = new ArrayAdapter<String>(this, android.R.layout.simple_list_item_1, items);
    list.setAdapter(adapter);
    list.setOnItemClickListener(mylistener);
}

public void changeFragment(Fragment f){
    FragmentTransaction ft = getFragmentManager().beginTransaction();
    ft.replace(R.id.fragment, f);
    ft.setTransition(FragmentTransaction.TRANSIT_FRAGMENT_FADE);
    ft.addToBackStack(null);
    ft.commit();
}

   public OnItemClickListener mylistener = new OnItemClickListener() {

    @Override
    public void onItemClick(AdapterView<?> parent, View view, int position,
            long id) {
        switch(position){
        case 0 : changeFragment(A); 
            break;
        case 1 : changeFragment(B); 
            break;
        }

    }
};

I know before i put a “replace” i have to remove but how can i remove the one i’m already in ?
What is telling me in the log :
The specified child already has a parent. You must call removeView() on the child’s parent first .

Answer 1

Have a look at the API demos FragmentLayout sample as it does something similar to what you want I believe. There’s nothing wrong with calling replace to load the first fragment as that sample demonstrates.

Firstly add some protection so when when you click on the same list entry you don’t reload the same fragment.

Secondly be careful when maintaining references to fragments, see link. You may want to recreate the fragments each time or use remove and add instead of replace.