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Home/ Questions/Q 7666961
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T14:58:27+00:00 2026-05-31T14:58:27+00:00

The title asks the question. Basically I am using a java library that takes

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The title asks the question. Basically I am using a java library that takes a String… as a parameter. How can I call that in my scala code?

I’ll add a bit more:

from scala code

def myScalaFunc(params:String*) {
   val myJavaClass = new JavaClass()
   myJavaClass(params)
}
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  1. Editorial Team
    Editorial Team
    2026-05-31T14:58:28+00:00Added an answer on May 31, 2026 at 2:58 pm

    You have to expand the params into a series of arguments, not just a single collection argument. The easiest way to do this is by saying params: _*.

    If the Java looks like:

    public class VarargTest {
      public void javaFunc(String... args) { 
        // something
      }
    }
    

    Then the Scala caller looks like:

    def scalaFunc(params: String*) = 
      (new VarargTest).javaFunc(params: _*)
    
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