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Home/ Questions/Q 3424764
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T06:30:47+00:00 2026-05-18T06:30:47+00:00

The title is a bit weird, so let me clarify. I have two objects,

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The title is a bit weird, so let me clarify.

I have two objects, Garage and Vehicle, in a one-to-many relationship. There are multiple types of vehicles, such as car and truck; the type is persisted as a string in the Vehicle table.

Here’s the two classes:

@Entity
@Table(...)
public class Garage {
    ....

    @Column(name = "garageId")
    private Integer garageId;

    @OneToMany
    @JoinColumn(name = "garageId")
    private Set<Vehicle> vehicles;

    ....
}

@Entity
@Table(...)
public class Vehicle {
    ....

    @Column(name = "garageId")
    private Integer garageId;

    //could be "Truck" or "Car"
    @Column(name = "type")
    private String type;

    ....
}

In order to differentiate between types of Vehicles, currently we have to look at the type column and use an enum. What I’d like to do is have subclasses of Vehicle, such are Car and Truck, to represent the different types rather than relying on the Type field. Then my code can instanceof to determine the type instead of using that field.

However, I don’t know how to tell Hibernate how to instantiate subclasses based on the value of the Type column, or if it even can.

I’d appreciate any help you guys can give. Thanks in advance!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-18T06:30:48+00:00Added an answer on May 18, 2026 at 6:30 am

    If you want to save the current database schema, you need to use SINGLE_TABLE inheritence strategy with type column as a discriminator:

    @Entity 
    @Table(...) 
    @Inheritance(strategy = InheritanceType.SINGLE_TABLE)
    @DiscriminatorColumn(name = "type")
    public abstract class Vehicle { ... }
    
    @Entity
    @DiscriminatorValue("...")
    public class Car extends Vehicle { ... }
    
    @Entity
    @DiscriminatorValue("...")
    public class Truck extends Vehicle { ... }
    
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