Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 7797913
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 1, 20262026-06-01T23:50:26+00:00 2026-06-01T23:50:26+00:00

The user inputs a text, then I check whether that string can be divided

  • 0

The user inputs a text, then I check whether that string can be divided by 8

if(text.length()%8==0)

If yes, I take the quotient.

int sk = text.length()/8;

And so I need to take each 8 symbols from that sentence and convert to a new different symbol. For example if the sentence is 1234567890123456 it has to be divided to 2 different symbols. 12345678 = A and 90123456 = B

To do that I know I should use for loop
I’ve done this:

if(text.length()%8==0){
            sk = text.length()/8;
            for(int m=1;m<=sk;m++){
                //change the text
            }
}

So, my question is, what to write down in that for loop in order to see the desired results?

-Thank you

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-01T23:50:28+00:00Added an answer on June 1, 2026 at 11:50 pm

    You can use the replace method from std::string:

    if(text.length()%8==0){
            sk = text.length()/8;
            for(int m=1;m<=sk;m++){
                text.replace(sk, sk+8, newString);
            }
    }
    

    Of course there are some checks you’ll need to perform.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I am trying to customize the error message displayed when a user inputs text
I'm trying to get edit text to behave in this way: User can input
When validating user inputs in an application that is to be run across multiple
When a user inputs a value in a certain column then this value should
I have a text field that can accept input of any kind. Based on
I'm building a website with Rails which can let user check if some domains
I have several applications within my domain that accept similar inputs in text fields.
How can I use javascript to check, if the user clicks out of my
in JOption pane I have some JTextArea where user must eneter some text. Then
I have an input box where the user can enter a string date, for

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.