Question

The vars are $ingval1 and so on.. the SQL fields are the same, obviously without the $..

This section of my script is not updating the table, why?

     <?php // post

     $basename1 = 'ingval';$basename2 = 'ingamt';
     $basename3 = 'ingdes';$basename4 = 'ingcode';

     for ($y = 1; $y < 26; $y++) { 
         $tempname1 = $basename1 . $y; $tempname2 = $basename2 . $y; 
         $tempname3 = $basename3 . $y; $tempname4 = $basename4 . $y;  
         $$tempname1 = $_POST['ingval'.$y];
         $$tempname2 = $_POST['ingamt'.$y];
         $$tempname3 = $_POST['ingdes'.$y];
         $$tempname4 = $_POST['ingcode'.$y];


    }       // sql insert


    $basename1 = 'ingval';$basename2 = 'ingamt';
    $basename3 = 'ingdes';$basename4 = 'ingcode';

    for ($y = 1; $y < 26; $y++) { 

        $tempname1 = $basename1 . $y; $tempname2 = $basename2 . $y; 
        $tempname3 = $basename3 . $y; $tempname4 = $basename4 . $y; 

        $sql = "UPDATE $cookbookdb SET  

           ingval.$y = '" . $$tempname1 . "',
           ingamt.$y = '" . $$tempname2 . "',
           ingdes.$y = '" . $$tempname3 . "',
           ingcode.$y = '" . $$tempname4 . "'


        WHERE id = '" . $barcodeinput . "'";

        sql_query($sql)or die(mysql_error());

    } ?>

I’ve tried this a few different ways and still no luck.

Answer 1

Why are you using variable variables in the update statement? It might be valid, but I cannot see any values from your code that would make it valid.

Should it be :

ingval.$y = '" . $tempname1 . "'

instead in your update statement?

From the code, the value of $tempname1 would be ingval1 through ingval26 but the value of $$tempname1 would be the value of the variable called $ingval1 through $ingval26 which I cannot see in the code at all.