Question

..then to an array, or along those lines. I’m so confused on what I’m supposed to do.

Here are the structs:

typedef struct {
  char name[30];
} PersonType;

typedef struct {
  PersonType *personInfo;
} StudentType;

typedef struct {
  StudentType students[30];
} GraduateType;

I want to get the name of the PersonType. Something like this, in main():

GraduateType *gptr = (GraduateType *) calloc(3, sizeof(GraduateType));
// Assume here that info has been scanf()'d
int i, j;
for(i = 0; i < 3; i++) {
  for(j = 0; j < 2; j++) {
    if(strcmp(gptr[i].students[j].personInfo.name, "asd")) { // <- This
      // blah
    }
  }
}

How?

Answer 1

You were almost there. personInfo is a pointer, so you should treat it as such:

gptr[i].students[j].personInfo->name