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Home/ Questions/Q 8526547
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T08:18:10+00:00 2026-06-11T08:18:10+00:00

There are a few posts relevant to this but I’m not seeing anything near

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There are a few posts relevant to this but I’m not seeing anything near to the situation I’m struggling with.

I’ve inherited a rather large codebase which the original designer has taken some interesting methods of design. I’m attempting to call a method of a class that’s defined. The class file itself has some global variables set. I call this method from a function, where also, I’ve included this file. When the method runs, the global variables are no longer defined. See below:

My File:

<?php //myScript.php

echo("Calling foo(): ");
foo();

function foo() {
   include '../../php/class.bar.php';
   $bar = new bar();
   $bar->doSomething();
}
?>

../../php/class.bar.php:

$GLOBAL_ARRAY_ONE[0] = 'Here I am';
$GLOBAL_ARRAY_ONE[1] = 'JT';

class bar {
   public $itsFoo = array();
   public $itsBar = array();

   public function doSomething() {
      global $GLOBAL_ARRAY_ONE;
      $this->itsFoo[0] = $GLOBAL_ARRAY_ONE[0];
      $this->itsFoo[1] = $GLOBAL_ARRAY_ONE[1];

      var_dump($this->itsFoo);
   }
}

So, when I run “myScript.php” The output is: calling foo(): NULL

I personally wouldn’t declare global arrays in a script like that but, I see no reason why I shouldn’t have access to them.

Any ideas? Thanks!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-11T08:18:12+00:00Added an answer on June 11, 2026 at 8:18 am

    Since you include the file inside a function – GLOBALS cannot be defined there (neither a class). What you probably want to do is to include class.bar.php outside (of foo()):

    <?php //myScript.php
    
    include '../../php/class.bar.php';
    
    echo("Calling foo(): ");
    foo();
    
    function foo() {   
       $bar = new bar();
       $bar->doSomething();
    }
    ?>
    
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