Question

There are about 50 files that need to be opened in my program for reading and i renamed all of them from 1.txt to 50.txt hoping i can pass the filename through a loop that increments the file number, but i don’t know how / don’t think it is possible to pass an integer to the char or is there a better way to workaround my situation.

char* filename = "";

for(int i =0; i < 50; i++)
{
if(i == 0){filename = "0.txt";}
if(i == 1){filename = "1.txt";} // ..
int num = 0, theinteger = 0;
ifstream in(filename, ios::binary);
unsigned char c;
while( in.read((char *)&c, 1) )
{       
        in >> theinteger;
        sca.chac[num]=theinteger; 
        num++;
}
}

return 0;

Answer 1

There is a relatively straightforward way to do it – in C, use sprintf function, like this:

char filename[100];
sprintf(filename, "%d.txt", i);

In C++, use ostringstream:

ostringstream oss;
oss << i << ".txt";