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Home/ Questions/Q 4068768
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T16:24:58+00:00 2026-05-20T16:24:58+00:00

There are many questions and answers here on StackOverflow that assume a letter can

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There are many questions and answers here on StackOverflow that assume a “letter” can be matched in a regexp by [a-zA-Z]. However with Unicode there are many more characters that most people would regard as a letter (all the Greek letters, Cyrllic .. and many more. Unicode defines many blocks each of which may have “letters”.

The Java definition defines Posix classes for things like alpha characters, but that is specified to only work with US-ASCII. The predefined character classes define words to consist of [a-zA-Z_0-9], which also excludes many letters.

So how do you properly match against Unicode strings? Is there some other library that gets this right?

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  1. Editorial Team
    Editorial Team
    2026-05-20T16:24:58+00:00Added an answer on May 20, 2026 at 4:24 pm

    Here you have a very nice explanation:

    http://www.regular-expressions.info/unicode.html

    Some hints:

    Java and .NET unfortunately do not support \X (yet). Use \P{M}\p{M}* as a substitute. To match any number of graphemes, use (?:\P{M}\p{M}*)+ instead of \X+.

    In Java, the regex token \uFFFF only matches the specified code point, even when you turned on canonical equivalence. However, the same syntax \uFFFF is also used to insert Unicode characters into literal strings in the Java source code. Pattern.compile("\u00E0") will match both the single-code-point and double-code-point encodings of à, while Pattern.compile("\\u00E0") matches only the single-code-point version. Remember that when writing a regex as a Java string literal, backslashes must be escaped. The former Java code compiles the regex à, while the latter compiles \u00E0. Depending on what you’re doing, the difference may be significant.

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