Question

There are two arrays that I’d like to save as CSV file from PHP. The problem is that this code works only for the first Call. E.g. in the below-given example I can save only array1, but array2 is not saved. If I swap places of array1 and array2, then array2 will be saved instead of array1. What’s actually wrong in my code and how could I solve this problem?

     header("Content-type: text/csv");
     header("Pragma: no-cache");
     $headers = array('xxx','yyy','zzz');
     saveCSV($array1,"file1.csv",$headers);

     header("Content-type: text/csv");
     header("Pragma: no-cache");
     $headers = array('aaa','bbb','ccc');   
     saveCSV($array2,"file2.csv",$headers);

function saveCSV($data,$fileName,$headers) {
    $outstream = fopen($fileName, "a");
    file_put_contents($fileName, "");

    if ($headers != 0)
        fputcsv($outstream,$headers);

    function __outputCSV(&$vals, $key, $filehandler) {
        fputcsv($filehandler, $vals);
    }
    array_walk($data, "__outputCSV", $outstream);
    fclose($outstream);
}

Answer 1

Your setting the headers, twice.

Trying building up your csv data output, then once completed set the headers once.

Also you have a function declaration within another, which i’m sure is invalid.

move __outputCSV somwehere else, or maybe you intended it to be a closure?