Question

There are two things to note right off the bat….

1. The shell script runs fine manually
2. A simple shell script (echo hello) that I wrote runs fine through java

So I have a shell script that I’m attempting to run through a Java process.

File sqlF = new File("path to deploy script");

Process proc = rt.exec(sqlF + "/deploy.sh");
proc.waitFor();

System.out.println(proc.exitValue());

When I run this code I get an ambiguous return value of “1”.

Here’s the shell script (because I imagine the issue may stem from here):

#!/bin/bash
mysql -u XXXX -h XXXXX < XXXXX.sql
mysql -u XXXX -h XXXXX database < DEPLOY-HELPER.sql

Any ideas as to why this would not execute properly from Java?

Answer 1

If you want to run a shell script you must explicitly invoke the shell and pass it the name of the script as an argument, as in

bash /path/to/script/deploy.sh

Neither Runtime.exec() nor ProcessBuilder know how to execute shell scripts themselves, they only know how to execute binary executables.