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Home/ Questions/Q 8975951
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T19:00:30+00:00 2026-06-15T19:00:30+00:00

There are two ways construct a class: class Cell{ public: Cell(int cellID, int nx);

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There are two ways construct a class:

  class Cell{
  public:
        Cell(int cellID, int nx);
        ~Cell();
  private:
        int cellID_;
        int nx;
  };

The first way:

  Cell::Cell(int cellID, int nx)
    : cellID_(cellID), nx_(nx){}

The second way :

  Cell::Cell(int cellID, int nx){init(cellID, nx)}

  void Cell::init(int cellID, int nx){
         cellID_ = cellID;
         nx_ = nx;
  }
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-15T19:00:32+00:00Added an answer on June 15, 2026 at 7:00 pm

    Performance:

    The first one is the best because it initializes the objects in true sense unlike second method which assigns the already initialized objects.

    Note that there is a little overhead when you use the second method:

    As you see there is an additional overhead of creation & assignment in the latter, which might be considerable for user defined classes.

    Cost of Member Initialization = Object Construction 
    Cost of Member Assignment = Object Construction + Assignment
    

    In case of members which are in-built/POD data types there is no overhead but if the members are non POD types then the overhead is significant.

    Necessity:

    Note that You will be forced to use the member initializer list in certain scenarios:

    • Your class has a reference member
    • Your class has a non static const member

    Such members cannot be assigned to but they must be initialized in member initializer list.


    Given the above as a practice the first method is always preferrable.

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