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Home/ Questions/Q 6752441
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T13:02:41+00:00 2026-05-26T13:02:41+00:00

There has got to be a faster way to do in place replacement of

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There has got to be a faster way to do in place replacement of values, right? I’ve got a 2D array representing a grid of elevations/bathymetry. I want to replace anything over 0 with NAN and this way is super slow:

for x in range(elevation.shape[0]):
    for y in range(elevation.shape[1]):
        if elevation[x,y] > 0:
            elevation[x,y] = numpy.NAN

It seems like that has so be a much better way!

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  1. Editorial Team
    Editorial Team
    2026-05-26T13:02:42+00:00Added an answer on May 26, 2026 at 1:02 pm

    The following will do it:

    elevation[elevation > 0] = numpy.NAN
    

    See Indexing with Boolean Arrays in the NumPy tutorial.

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