Question

there is a check I need to perform after each subsequent step in a function, so I wanted to define that step as a function within a function.

>>> def gs(a,b): ...   def ry(): ...     if a==b: ...       return a ... ...   ry() ... ...   a += 1 ...   ry() ... ...   b*=2 ...   ry() ...  >>> gs(1,2) # should return 2 >>> gs(1,1) # should return 1 >>> gs(5,3) # should return 6 >>> gs(2,3) # should return 3 

so how do I get gs to return ‘a’ from within ry? I thought of using super but think that’s only for classes.

Thanks

There’s been a little confusion… I only want to return a if a==b. if a!=b, then I don’t want gs to return anything yet.

edit: I now think decorators might be the best solution.

Answer 1

This should allow you to keep checking the state and return from the outer function if a and b ever end up the same:

def gs(a,b):     class SameEvent(Exception):         pass     def ry():         if a==b:             raise SameEvent(a)     try:         # Do stuff here, and call ry whenever you want to return if they are the same.         ry()          # It will now return 3.         a = b = 3         ry()      except SameEvent as e:         return e.args[0]