Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 5929131
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 22, 20262026-05-22T14:22:53+00:00 2026-05-22T14:22:53+00:00

There is a code of an unknown function: function Magic(number) r = number mod

  • 0

There is a code of an unknown function:

function Magic(number)
    r = number mod 2
    print r
    if number > 1
        Magic(number / 2)

(written in pseudo-code)

The question is: what integer number should be passed in order to receive the following answer

0 1 1 0 0 1

The main problem is that I can’t figure out how mod is working in pseudocode.
Should 5,5 mod 3 = 2.5 or 2

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-22T14:22:53+00:00Added an answer on May 22, 2026 at 2:22 pm

    First of all, here is executable python code for this problem.

    def Magic(number):
    r = number % 2
    print r
    if number > 1:
        Magic(number / 2)
    
    Magic(15)       
    

    However, the pattern in this problem is that the function is returning the REVERSE binary number for the given input number. So, in this instance, the easiest solution would be to take 0 1 1 0 0 1, reverse it to 100110, and calculate the value of that binary number, which is 32 + 4 + 2 = 38. Using this methodology, you can calculate the required number or the expected output for any given input.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

Is there code in VBA I can wrap a function with that will let
There is code for save button, but I can't see any code behind the
Is there any code coverage tool available for PHP? I wish to check the
Are there any Code Generators that would take a well-formed XML document, and write
Is there any code or custom options available to achieve the following : 1>
In the code there exists exactly one type that implements IResourceConverter. That's what the
In my code there are some calls to a method that set the values
Is there any code example teaching how to zoom in and out in a
In some existing code there is a test to see if the user is
In a .f file there is code that does this: real Bob, avar ...

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.