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Home/ Questions/Q 7045673
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T02:33:33+00:00 2026-05-28T02:33:33+00:00

There is a list: List<Integer[]> myList = new ArrayList<Integer[]>(); It contains a sigle entry,

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There is a list:

List<Integer[]> myList = new ArrayList<Integer[]>();

It contains a sigle entry, but might contain multiple entries:

myList = [[2,null,1,null,null,3,6,1,1]]

I need to convert this list into the array Integer[][], but the conversion fails due to nulls:

Integer[] myArr = myList.toArray(new Integer[myList.size()]);

How to solve this issue?

Edit#1

I need to get:

myArr = [2,null,1,null,null,3,6,1,1]
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  1. Editorial Team
    Editorial Team
    2026-05-28T02:33:34+00:00Added an answer on May 28, 2026 at 2:33 am

    Try this (assuming you have actually the List<Integer[]> you talked about in your comment):

    List<Integer[]> myList = new ArrayList<Integer[]>();
    myList.add(new Integer[] {2,null,1,null,null,3,6,1,1} );
    
    Integer[][] myArr = myList.toArray(new Integer[myList.size()][]);
    

    If you convert a list of arrays to an array, you’ll get a 2 dimensional array and thus your parameter should be one too.

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