Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 4581182
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 21, 20262026-05-21T20:53:19+00:00 2026-05-21T20:53:19+00:00

There is a set visited . And I wanna check all its elements from

  • 0

There is a set visited. And I wanna check all its elements from 4-th to last.
I’m trying to do something like that

int visited_pointer = 4;
for ( set<int>::iterator i_visited=visited.begin()+visited_pointer
    ; i_visited!=visited.end()
    ; i_visited++
)

and got errors with operator+.

How can I do that in the right way?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-21T20:53:20+00:00Added an answer on May 21, 2026 at 8:53 pm

    That usage of operator+ is only provided for random-access iterators. set iterators are bi-directional iterators.

    But the function std::advance can be used to move any iterator a certain number of places:

    #include <iterator>
    
    //...
    
    set<int>::iterator i_visited = visited.begin();
    for ( std::advance(i_visited, visited_pointer)
        ; i_visited!=visited.end()
        ; ++i_visited
    )
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

There are a set of questions that seem to be commonly-used in interviews and
There are a set of point that are collinear. The problem is to add
Is there any way to set the same icon to all my forms without
Is there an algorithm or set of algorithms that would let you find the
I appreciate there is no 'set' answer to this question. I am trying to
There is an A set of elements indexed [0, n]. At any time at
Is there a way set flags on a per-file basis with automake? In particular,
Is there any free set of forms, icons, styles, images, etc for building web-based
In the java world there is a set of classes optimized for concurrent tasks.
If there is a cookie set for a subdomain, metric.foo.com, is there a way

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.