Question

There is a similar question on SO which suggests using NumberFormat which is what I have done.

I am using the parse() method of NumberFormat.

public static void main(String[] args) throws ParseException{

    DecToTime dtt = new DecToTime();
    dtt.decToTime("1.930000000000E+02");

}

public void decToTime(String angle) throws ParseException{

    DecimalFormat dform = new DecimalFormat();
    //ParsePosition pp = new ParsePosition(13);
    Number angleAsNumber = dform.parse(angle);

    System.out.println(angleAsNumber);
}

The result I get is

1.93

I didn’t really expect this to work because 1.930000000000E+02 is a pretty unusual looking number, do I have to do some string parsing first to remove the zeros? Or is there a quick and elegant way?

Answer 1

When you use DecimalFormat with an expression in scientific notation, you need to specify a pattern. Try something like

DecimalFormat dform = new DecimalFormat("0.###E0");

See the javadocs for DecimalFormat — there’s a section marked “Scientific Notation”.