Question

There is a table which shows employee’s daily program.

SELECT COUNT(*) AS TotalDay FROM [User]
    INNER JOIN [x] ON [x].UserID = [User].ID  
WHERE       
        StartTime BETWEEN '20120611' AND '20120618' AND UserID = 20
GROUP BY [User].ID, [User].Name
ORDER BY Name

it return 7 records. because in one day, one user ( UserID) can go two different places.

For example,
This user went A place from 20120611 08:30:00 to 20120611 13:30:00
and went B place from 20120611 14:00:00 to 20120611 19:00:00

and this return 2 records when I use below query.

SELECT COUNT(*) AS TotalDay FROM [User]
     INNER JOIN [x] ON [x].UserID = [User].ID  
WHERE       
        StartTime = '20120611' AND UserID = 20
GROUP BY [User].ID, [User].Name
ORDER BY Name

But I want to get one record because that operations were in one day.

So how can I get it?

I use MSSQL. StartTime is datetime in sql.

Answer 1

Try following in your where clause:

DATEADD(DD, DATEDIFF(DD, 0, STARTTIME), 0)  BETWEEN DATEADD(DD, DATEDIFF(DD, 0, <DATE_TIME_PARAMETER>), 0) AND DATEADD(DD, DATEDIFF(DD, 0, <DATE_TIME_PARAMETER>), 0)

You will also need to group the results by above mentioned date part.