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Home/ Questions/Q 6538713
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T10:46:04+00:00 2026-05-25T10:46:04+00:00

There is an example of how to modify SortableBindingList to use a stable sort.

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There is an example of how to modify SortableBindingList to use a stable sort. However, there is an updated version of SortableBindingList. What is the best way to modify this new version to use a stable sort? I think I would want a flag on the SortableBindingList to let the user of the SortableBindingList decide if they want to use (slower) stable sort or (faster) default sort.

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  1. Editorial Team
    Editorial Team
    2026-05-25T10:46:05+00:00Added an answer on May 25, 2026 at 10:46 am

    You can solve this problem by writing a stable sort extension method for List<T>:

    public static class ListExtensions
    {
        public static void StableSort<T>(this List<T> list, IComparer<T> comparer)
        {
            var pairs = list.Select((value, index) => Tuple.Create(value, index)).ToList();
            pairs.Sort((x, y) =>
                {
                    int result = comparer.Compare(x.Item1, y.Item1);
                    return result != 0 ? result : x.Item2 - y.Item2;
                });
            list.Clear();
            list.AddRange(pairs.Select(key => key.Item1));
        }
    }
    

    and then in the new version of SortableBindingList change this line:

    itemsList.Sort(comparer);
    

    to:

    itemsList.StableSort(comparer);
    

    This works by using the unstable sort supplemented with a secondary key on the item index within the list. Since this version doesn’t use the pathologically slow insertion sort to achieve a stable sort, it should be fast enough for general use.

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