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Home/ Questions/Q 6083705
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T11:26:04+00:00 2026-05-23T11:26:04+00:00

there is few text boxes im generating dynamically with a counter so its looks

  • 0

there is few text boxes im generating dynamically with a counter so its looks like this

form.append('Street: <input type="text" id="street'+counter+'" /> city: <input type="text" id="city'+counter+'" /><br/>'); 
counter++;

then im doing this to make a array

var array = [];
for(i=1; i<counter; i++){
array.push({'a':$('#street' + i).val(),'b':$('#city' + i).val()});          
}   
console.log(array);
$.ajax({
  type: "POST",
  url: "dummy.php",
  data: array,
  success: function(response, textStatus, xhr) {
  },
  error: function(xhr, textStatus, errorThrown) {
  }
});

but the problem is when im trying to send array to php script via ajax im getting
Parameters
undefined undefined
undefined undefined

in post section of firebug

what im doing wrong here?

firebug console looks like with console.log(array) firebug output

Regards

Seems like i found the solution
i sent data like
data: {Addresses:array},
and it works

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T11:26:05+00:00Added an answer on May 23, 2026 at 11:26 am

    You could send your form as-is like this (don’t send as array):

    $.ajax({
      ...
      data: form.serialize()
      ...
    });
    

    and turn it to an array in your server code.

    Or, alternatively, you could name your inputs in a way they will automagically become two arrays on the server:

    form.append('Street: <input type="text" name="street[]" /> city: <input type="text" name="city[]" /><br/>'); 
    $.ajax({
      ...
      data: form.serialize()
      ...
    });
    

    And your PHP script would recieve $_POST['street'] and $_POST['city'] as arrays.
    Hope this helps. Cheers

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