Question

There is one thing regarding the usage of pointers here I do not understand Cell *curr = head; here takes the address of head and what does it do with it?

Cell *ConvertToListIter(Vector<int>& vector)
{
    Cell *head = new Cell;
    head->next = NULL;
    head->value = vector[0];
    Cell *curr = head;

    for (int i = 1; i < vector.size(); i++) {
        Cell *newCell = new Cell;
        newCell->next = NULL;
        newCell->value = vector[i];
        curr->next = newCell;
        newCell = curr;
    }

    return head;
}

Answer 1

Cell *curr = head; does not take the address of head — it takes the value of head. It just so happens that head is a pointer:

Cell *head = new Cell;

So, after Cell *curr = head; has executed, both curr and head point to the same thing.

Edit per your comment:

So if i then delete one of them it will affect both? they point to the
same address in memory, not two copies of the same value yes?

That’s correct. The two pointers point to a single object in memory. That object needs to be deleteed only once. In fact, attempting to delete it twice will result in Undefined Behavior, and very often it will crash your program.