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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T06:22:57+00:00 2026-05-12T06:22:57+00:00

There is probably a really simple answer to this but I just can’t see

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There is probably a really simple answer to this but I just can’t see it.

#include <stdio.h>

int main(void) {
int x = 0;
printf("\n%d\n%d\n",x,&x);
}

Okay, so the printf gives 0 (x) and 2293752 (&x). I am trying to figure out a way to look at any address (&) and see what is already stored there. This is just for experimentation. Any help?

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  1. Editorial Team
    Editorial Team
    2026-05-12T06:22:57+00:00Added an answer on May 12, 2026 at 6:22 am
    void* memAddr = (void*)0xAABBCCDD; //put your memory address here
    printf("int value at memory address %p is %i", memAddr, *((int*)memAddr));
    

    You’ll probably find that examining arbitrary memory addresses will just cause a crash.

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