Question

There is simple code

int a( int *p0 ) {
        int p;
        if( p0 ) return p0 > &p;
        return a(&p);
}

int main() {
        puts( a(0) ? "y" : "n" );
}

What result will be and how many times method a will be called?

Answer 1

Comparing pointers using > is unspecified if they are not part of the same array.

So there is no actual answer, although you can assume if the stack grows down if( p0 ) return p0 > &p; will be true, otherwise false.