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Asked: May 10, 20262026-05-10T17:23:42+00:00 2026-05-10T17:23:42+00:00

There is some magic going on with WCF deserialization. How does it instantiate an

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There is some magic going on with WCF deserialization. How does it instantiate an instance of the data contract type without calling its constructor?

For example, consider this data contract:

[DataContract] public sealed class CreateMe {    [DataMember] private readonly string _name;    [DataMember] private readonly int _age;    private readonly bool _wasConstructorCalled;     public CreateMe()    {       _wasConstructorCalled = true;    }     // ... other members here } 

When obtaining an instance of this object via DataContractSerializer you will see that the field _wasConstructorCalled is false.

So, how does WCF do this? Is this a technique that others can use too, or is it hidden away from us?

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1 Answer

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  1. 2026-05-10T17:23:43+00:00Added an answer on May 10, 2026 at 5:23 pm

    FormatterServices.GetUninitializedObject() will create an instance without calling a constructor. I found this class by using Reflector and digging through some of the core .Net serialization classes.

    I tested it using the sample code below and it looks like it works great:

    using System; using System.Reflection; using System.Runtime.Serialization;  namespace NoConstructorThingy {     class Program     {         static void Main()         {             // does not call ctor             var myClass = (MyClass)FormatterServices.GetUninitializedObject(typeof(MyClass));              Console.WriteLine(myClass.One); // writes '0', constructor not called             Console.WriteLine(myClass.Two); // writes '0', field initializer not called         }     }      public class MyClass     {         public MyClass()         {             Console.WriteLine('MyClass ctor called.');             One = 1;         }          public int One { get; private set; }         public readonly int Two = 2;     } } 

    http://d3j5vwomefv46c.cloudfront.net/photos/large/687556261.png

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