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Home/ Questions/Q 6718463
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T08:58:20+00:00 2026-05-26T08:58:20+00:00

There is some nasty legacy code. std::string xxx = GetCommand(); // get CommandX; if

  • 0

There is some nasty legacy code.

std::string xxx = GetCommand(); // get "CommandX";
if (xxx == "Command1")
{
    return new Command1();
}
else if (xxx == "Command2")
{
    return new Command2();
}
...
else if (xxx == "Command100")
{
    return new Command100();
}

I want to improve this code structure.
There were too many comparison. So I put them to a map.

for (int i = 0; i < GetCommandCount(); ++i)
{
    // key is a command string
    // value is a function pointer which creates it's instance
    map.insert(command, a function pointer);
}

// then

ICommand* pCommand = map.getInstance(command);

But this way has to make additional function every time if new command comes.
Yes, the functions might be reasonable. But all the functions just be return new CommandNNN(); I guess there is the way to remove the duplication.

How do you think?

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  1. Editorial Team
    Editorial Team
    2026-05-26T08:58:21+00:00Added an answer on May 26, 2026 at 8:58 am

    Since all the functions are return new CommandNNN();, you can use a template function:

    template <class T>
    CommandBase* createCommand() {
        return new T();
    }
    

    and bind to this function in your map:

    map.insert(std::make_pair("Command1", &createCommand<Command1>));
    map.insert(std::make_pair("Command2", &createCommand<Command2>));
    map.insert(std::make_pair("Command3", &createCommand<Command3>));
    

    This lets you avoid creating a new function for each command. However, there would still be some duplication in the map.insert-statements. This could be further reduced by using macros, if that’s your cup of tea:

    #define INSERT(cmd) map.insert(std::make_pair(#cmd, &createCommand<cmd>));
    
    INSERT(Command1);
    INSERT(Command2);
    INSERT(Command3);
    
    #undef INSERT
    

    or

    #define INSERT(n) map.insert(std::make_pair("Command" #n, &createCommand<Command ## n>));
    
    INSERT(1);
    INSERT(2);
    INSERT(3);
    
    #undef INSERT
    

    I suspect that you can even get the preprocessor to do some counting for you, but that’s outside of my domain.


    Applying even more macros, as well as some global state, both of which are frowned upon by many, you can get even tighter coupling:

    #include <map>
    #include <string>
    #include <cassert>
    
    class CommandBase {};
    
    static std::map<std::string, CommandBase* (*)()> g_commandMap;
    
    template <class C>
    CommandBase* createCommand() {
        return new C();
    }
    
    class CommandRegistrer {
    public:
        CommandRegistrer(const std::string& name, CommandBase* (*instantiator)()) {
            g_commandMap.insert(std::make_pair(name, instantiator));
        }
    };
    
    #define COMMAND_CLASS(n) \
        class Command##n; \
        CommandRegistrer g_commandRegistrer##n("Command" #n, createCommand<Command##n>); \
        class Command##n : public CommandBase
    
    COMMAND_CLASS(1) { /* implementation here */ };
    COMMAND_CLASS(2) { /* implementation here */ };
    
    int main() {
        assert(g_commandMap.find("Command1") != g_commandMap.end());
    }
    
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