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Home/ Questions/Q 7003947
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T21:08:06+00:00 2026-05-27T21:08:06+00:00

There is this code: class Sample: variable = 2 object1 = Sample() object2 =

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There is this code:

class Sample:
    variable = 2
object1 = Sample()
object2 = Sample()
print object1.variable  # 2
print object2.variable  # 2
object1.variable = 1
print object1.variable  # 1
print object2.variable  # 2 <- why not 1 too?

Why object2.variable is not also 1 after assignment to class variable?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T21:08:07+00:00Added an answer on May 27, 2026 at 9:08 pm

    Don’t confuse this with a static variable. In your case, both objects have a name variable point to a 2 object after instantiation. Now if you change the variable to 1 in one object, all you do is bind the name to a different object, i.e. the 1 object. The name in object2 still refers to a 2 object. The original class object is untouched and still has the name variable point to a 2, so object3 = Sample() will have a 2 bound to variable as well.

    One way to get around this is to write the class like the following:

    >>> class Sample:
    ...     variable=[2]
    ... 
    >>> object1 = Sample()
    >>> object2 = Sample()
    >>> print object1.variable[0]; print object2.variable[0]
    2
    2
    >>> object1.variable[0]=1
    >>> print object1.variable[0]; print object2.variable[0]
    1
    1
    

    This is because all classes bind the name variable to the same, muatable object, and you manipulate the contents of this same object (variable[0]).

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