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Home/ Questions/Q 8721171
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T07:10:38+00:00 2026-06-13T07:10:38+00:00

There must a be a (very) quick and efficient way to get only elements

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There must a be a (very) quick and efficient way to get only elements from a numpy array, or even more interestingly from a slice of it.
Suppose I have a numpy array:

import numpy as np
a = np.arange(-10,10)

Now if I have a list:

s = [9, 12, 13, 14]

I can select elements from a:

a[s]  #array([-1,  2,  3,  4])

How can I have an (numpy) array made of the elements from a[s] that fulfill a condition, i.e. are positive (or negative)?
It should result

np.ifcondition(a[s]>0, a[s])  #array([2,  3,  4])

It looks trivial but I was not able to find a simple and condensed expression. I’m sure masks do but it’s doesn’t look really direct to me.
However, neither:

a[a[s]>0]
a[s[a[s]>0]]

are in fact good choices.

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  1. Editorial Team
    Editorial Team
    2026-06-13T07:10:39+00:00Added an answer on June 13, 2026 at 7:10 am

    How about:

    In [19]: b = a[s]
    
    In [20]: b[b > 0]
    Out[20]: array([2, 3, 4])
    
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