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Home/ Questions/Q 6190157
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T02:32:12+00:00 2026-05-24T02:32:12+00:00

There’s many instances of code similar to this in the codebase I’m working in

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There’s many instances of code similar to this in the codebase I’m working in these days. This is a thin C wrapper aroundthe OS API.

// From the OS
HANDLE CreateObject();
void CloseHandle(HANDLE);

typedef struct tagFOO {} FOO;

FOO* Foo_New()
{
    return (FOO*)CreateObject();
}

void Foo_Delete(FOO* foo)
{
    if(foo != NULL)
    {
        CloseHandle((HANDLE)foo);
    }
}

void Foo_Bar(FOO* foo)
{
    if(foo != NULL)
    {
        HANDLE h = (HANDLE)foo;
        // Do something interesting with h
    }
}

This seems to work and I want to avoid touching it if I can, but is this well defined? It seems very fishy to me

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-24T02:32:13+00:00Added an answer on May 24, 2026 at 2:32 am

    The C99 standard says:

    6.7.2.1 Structure and union specifiers

    Syntax

    struct-or-union-specifier:
           struct-or-union identifieropt { struct-declaration-list }
           struct-or-union identifier
    struct-or-union:
           struct
           union
    struct-declaration-list:
           struct-declaration
           struct-declaration-list struct-declaration
    

    Officially, that precludes your empty structure definition (and so does §6.5.2.1 in the C89 standard); there should be at least one member in the structure. However, you have to push GCC fairly hard to get it to complain; I used -std=c99 -pedantic and only with the -pedantic did it warn ‘struct has no members’.

    In my view, you would be better off (more strictly portable) with:

    typedef struct tagFOO FOO;
    

    Or, even using:

    typedef struct FOO FOO;
    
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