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Editorial Team
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Asked: 2026-06-18T06:38:02+00:00

They both seem to output the same results and turn strings into numbers. Is

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They both seem to output the same results and turn strings into numbers. Is there a difference I am not aware about? I can’t seem to find any documentation regarding ~~ operator.

var hey = true
hey = +hey //hey = 1

var hey = true 
hey = ~~hey //hey = 1

var num = "1231"
num = ~~num //num = 1231

var num = "1231"
num = +num //num = 1231

There is one difference that I found and that’s ~~ will always try to output a number whereas there are cases for + to simply return NaN

num = "omfg"
num = ~~num //num = 0

num = "omfg"
num = +num //num = NaN

num = {}
num = ~~num //num = 0

num = {}
num = +num //num = NaN

Any clarification would be awesome 🙂

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1 Answer

  1. Editorial Team

    Both will implicitly turn the operand into a number, because the operators can only be used on a number.

    The difference is that the ~ operator is a bitwise operator, so it will also turn the number into a 32 bit integer. (The result will still be of the type Number though, i.e. a double precision floating point number.)

    Neither is a descriptive way to turn a value into a number, as they both use a side effect of the actual operation. Normally you would use a function like parseInt or parseFloat to convert a string to a number.

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