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Home/ Questions/Q 6998381
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T20:24:16+00:00 2026-05-27T20:24:16+00:00

They can be defined like this Struct.new(:x, :y) But what can usefully be done

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They can be defined like this

Struct.new(:x, :y)

But what can usefully be done with them? Specifically, how can I create an instance of such a struct? This doesn’t work

Struct.new(:x => 1, :y => 1)

(you get TypeError: can't convert Hash into String).

I’m using Ruby 1.9.2.

UPDATE:

Good pointers so far, thanks. I suppose the reason I asked this was that I have several times found myself wanting to do this

Struct.new(:x => 1, :y => 1)

just so that I can pass an object around where I can write obj.x instead of, say, instantiating a hash and having to write obj[:x]. In this case I want the structure to be really anonymous – I don’t want to pollute my namespace with anything by naming what is returned from the Struct.new call. The closest thing to that, as already suggested is

Struct.new(:x, :y).new(1, 1)

But how do you like them apples? I’m not sure I do. Is it reasonable to expect to be able to define and instantiate an anonymous struct in one go (as part of core Ruby)? I guess when I read the official Ruby docs on Struct.new I assume the word ‘anonymous’ allows this, but it doesn’t.

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  1. Editorial Team
    Editorial Team
    2026-05-27T20:24:17+00:00Added an answer on May 27, 2026 at 8:24 pm

    Struct.new returns a Class, so you can, for example, assign it to a constant like this:

    Point = Struct.new(:x, :y)
    

    or subclass it:

    class Point < Struct.new(:x, :y)
      # custom methods here
      # ...
    end
    

    In both cases, you can use the resulting class like this:

    Point.new(3, 5)
    

    If you don’t want to create a specific class (because you need to instantiate an object of that class only once), consider to use OpenStruct instead:

    require 'ostruct'
    
    point = OpenStruct.new(:x => 3, :y => 5)
    
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