Question

This chunk of code is in a exercise from the book named C programming-A Modern Approach.

for(i=10;i>=1;i/=2)
{
    printf("%d", i++);
}

Edited:

The first output should be 10 and it should increase by 1 for the next step in the loop.But when i run this code all i get is 1 and it never ceases to print 1.

Please help me understand this code.

Answer 1

This code says

for( start with 10 ; as long as it is greater or equals 1 ; divide i by 2){
    Print i;
    add 1 to i
}

So:

start with 10:
print 10;
10 + 1 = 11
11 / 2 = 5,5 = 5 because it's int
print 5
5 + 1 = 6
6 / 2 = 3
print 3
3 + 1 = 4
4 / 2 = 2
print 2
2 + 1 = 3
3 / 2 = 1
print 1
1 + 1 = 2
2 / 2 = 1
print 1
1 + 1 = 2
2 / 2 = 1
.... and it will continue forever and ever

Execution order of for loops:

for([init];[1];[3]){
    [2]
}

Of course the order [1],[2],[3] is repeated until [1] is not true anymore