Question

This code…

#!/bin/bash

cond=10;

for i in {1..$cond}
do
    echo hello;
done

…just drives me crazy. This prints only one ‘hello’, as in i there is {1..10}.

#!/bin/bash

cond=10;

for i in {1..10}
do
    echo hello;
done

prints 10x hello, which is desired. How to put the variable into the condition? I tried different approaches, none of them worked. What a easy task though.. Thank you in advance.

Answer 1

This will work:

cond=10;

for ((i=0;i<=$cond;i++));
do
    echo hello;
done