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Home/ Questions/Q 7725159
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T04:52:12+00:00 2026-06-01T04:52:12+00:00

This code compiles: import java.io.Serializable; import java.util.Arrays; class Test<T extends Arrays & Serializable> {

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This code compiles:

import java.io.Serializable;
import java.util.Arrays;
class Test<T extends Arrays & Serializable> { }

but if I replace the last line with

class Test<T extends Serializable & Arrays> { }

I get “interface expected here”. Why?

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  1. Editorial Team
    Editorial Team
    2026-06-01T04:52:13+00:00Added an answer on June 1, 2026 at 4:52 am

    From section 4.4 of the JLS:

    Every type variable declared as a type parameter has a bound. If no bound is declared for a type variable, Object is assumed. If a bound is declared, it consists of either:

    • a single type variable T, or

    • a class or interface type T possibly followed by interface types I1 & … & In.

    It is a compile-time error if any of the types I1 … In is a class type or type variable.

    So basically, if your bounds include a class, it has to be the first bound.

    (Given that Arrays can’t be instantiated, it’s unclear why you would want a bound including it, mind you… was this just an example?)

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