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Home/ Questions/Q 6224937
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T08:45:16+00:00 2026-05-24T08:45:16+00:00

This code crashes at the cout line. Can anyone explain why this doesn’t work?

  • 0

This code crashes at the cout line. Can anyone explain why this doesn’t work?

#include <iostream>
#include <string>

using namespace std;

class myclass {
   const string& m_str;

public:
   myclass(string s) : m_str(s) {}
   const string& getString() const { return m_str; }
};

int main () {
   const string str("honey");
   myclass mc(str);
   cout << mc.getString() << "\n";
   return 0;
}
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  1. Editorial Team
    Editorial Team
    2026-05-24T08:45:17+00:00Added an answer on May 24, 2026 at 8:45 am

    the myclass constructor is taking a string by value which makes it a temporary. You’re then binding this temporary to the m_str member. As soo as the constructor exits your member reference becomes invalid. Instead: myclass(const string& s) : m_str(s) {}

    Even so that may not be a good idea. Generally speaking using references as members can be dangerous because you have to be very clear about lifetime semantics. You should consider just storing the string by value in your class unless you have a specific reason not to do so.

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