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Home/ Questions/Q 8982981
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T20:43:07+00:00 2026-06-15T20:43:07+00:00

this code does not compile but i don’t why, also the typeid() function can

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this code does not compile but i don’t why, also the typeid() function can take int as input parameter so the problem must be related to the template mechanism but i don’t get the rationale behind this fail.

#include <iostream>
#include <typeinfo>

template<typename T> void func(T)
{
  std::cout << typeid(T).name() << std::endl;
}

int main()
{
  func(int);  
  return(0);
}

What is wrong with this template/code ?

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  1. Editorial Team
    Editorial Team
    2026-06-15T20:43:08+00:00Added an answer on June 15, 2026 at 8:43 pm

    You need to pass an instance of type int, not the type itself:

    func(int());
            ^^ note the parentheses
    

    If you don’t want to pass an instance around, you could change your code like so:

    #include <iostream>
    #include <typeinfo>
    
    template<typename T> void func()
    {
      std::cout << typeid(T).name() << std::endl;
    }
    
    int main()
    {
      func<int>();
      return(0);
    }
    
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