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Home/ Questions/Q 8388775
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T18:32:45+00:00 2026-06-09T18:32:45+00:00

This code doesn’t do anything special. It’s just a snippet to show the problem

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This code doesn’t do anything special. It’s just a snippet to show the problem with forward declarations. Just a short question: why doesn’t it work and how to force it to work?

class A;

class B {
    A obj;
public:
    int getB() const {
        return 0;
    }
    void doSmth() {
        int a = obj.getA();
    }
};

class A {
    B obj;
public:
    int getA() const {
        return 1;
    }
    void doSomething() {
        int b = obj.getB();
    }
};

This code gives me errors:

error C2079: 'B::obj' uses undefined class 'A'
error C2228: left of '.getA' must have class/struct/union
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-09T18:32:47+00:00Added an answer on June 9, 2026 at 6:32 pm

    That type of circular dependency is not possible in C++. You can’t have objects containing each other. You can however store pointers or references. You also can’t really use a method of a class without the full definition.

    So, there’s two things you need to do:

    1) Replace the objects with pointers.

    2) Implement the method after the class definitions. If these are in a header, you’ll need to mark them as inline to prevent multiple definitions.

    class A;
    class B {
        std::shared_ptr<A> obj;
    public:
        int getB() const;
        void doSmth();
    };
    
    class A {
        std::shared_ptr<B> obj;
    public:
        int getA() const;
        void doSomething();
    };
    
    
    inline int B::getB() const {
            return 0;
        }
    inline void B::doSmth() {
            int a = obj->getA();
        }
    
    
    inline int A::getA() const {
            return 1;
        }
    inline void A::doSomething() {
            int b = obj->getB();
        }
    
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