Question

this code gives “Incorrectly set or registered parameter” SQLException. Can anyone help please?

OracleConnection conn = getAppConnection();
String q = "BEGIN INSERT INTO tb (id) values (claim_seq.nextval) returning id into :newId; end;" ;
CallableStatement cs = (OracleCallableStatement) conn.prepareCall(q);
cs.registerOutParameter("newId", OracleTypes.NUMBER);
cs.execute();
int newId = cs.getInt("newId");

Answer 1

JDBC does not support named binding, so it stops here.

Either live with indexed placeholders ? or add an extra abstraction layer on top of JDBC which supports named parameters, e.g. Hibernate and/or JPA.

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See also:

• JDBC tutorial
• Hibernate manual, chapter 10.4.1.4 – Bind Parameters