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Home/ Questions/Q 8450895
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T11:05:53+00:00 2026-06-10T11:05:53+00:00

This code is supposed to update the database record for the given book. There

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This code is supposed to update the database record for the given book. There is form that passes this function the rquired data and there are no errors in that form but I fear that I have formated my query to UPDATE MySQL incorrectly. Can someone verify this for me? I seem to always have trouble remember the formatting of a MySQL query string. If anyone has tips on how to remember it quickly without looking at documentation that would be greatly appreciated.

function saveBook ($ID, $Title, $Author, $Type, $Section, $AvailableMaterial)
{
    $query = "UPDATE Publications SET Title = '$Title', Author = '$Author', Section = '$Section', Type = '$Type', AvailableMaterial = '$AvailableMaterial' WHERE ID = '$ID'";
$result = mysql_query($query);
    if (!$result)
    {
    die('Query Failed: ' . mysql_error());
    }
    return HEADER ("LOCATION: /lightBox/close.php");
}
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  1. Editorial Team
    Editorial Team
    2026-06-10T11:05:54+00:00Added an answer on June 10, 2026 at 11:05 am

    No this code is not correct.

     $query = "UPDATE Publications SET `Title` = '".$Title."', `Author` = '".$Author."', `Section` = '".$Section."', `Type` = '".$Type."', `AvailableMaterial` = '".$AvailableMaterial."' WHERE `ID` = '".(int)$ID."'";
    

    is better. type is a reserved key in mysql, so you need backtics.

    And I assume you escape all your data before sending it to “savebook”

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