Question

This code keeps giving me a dead code warning on the i++ in the for loop and it is not incrementing the i for some reason!

import java.util.Scanner;


public class HideThatNumber {

    /**
     * @param args
     */
    public static void main(String[] args) {
        Scanner input=new Scanner(System.in);
        int enc=input.nextInt();
        int tur=0;
        String test="";
        double x;
        for (int i=1;i<10;i++){
            test="";
            test+=i;
            test+=enc;
            x=Integer.parseInt(test);
            x/=11;
            if(x==Math.round(x));{
                tur=i;
                break;
            }
        }
        if(tur==0)
            System.out.println("Impossible");
        else 
            System.out.println(Integer.parseInt(test)/11);
    }
}

Answer 1

    if(x==Math.round(x)); <--semi-colon
    {
        tur=i;
        break;
    }

Inside your for loop, you have put a semi-colon at the end of your if. Thus the next block of code will be executed in any case, and thus you would break out of your loop after the first iteration.

    {
        tur=i;
        break;
    }

This block will be executed regardless of what your if condition evaluate to. And you break out of the loop.

And hence you get the warning, because i++ will never be executed.