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Home/ Questions/Q 778129
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T19:42:56+00:00 2026-05-14T19:42:56+00:00

This code $(#loading).ajaxStart(function() { alert(start); $(this).show(); }); in my mark-up <div style=text-align:center;><img id=loading src=../images/common/loading.gif

  • 0

This code

$("#loading").ajaxStart(function() {
        alert("start");
        $(this).show();
    });

in my mark-up

<div style="text-align:center;"><img id="loading" src="../images/common/loading.gif" alt="" /></div>

Here is the full ajax request:

$.ajax({
        type: "POST",       

        url: "http://localhost/WebServices/Service.asmx/GetResults",

        data: jsonText,
        contentType: "application/json; charset=utf-8",
        dataType: "json",
        success: function(response) {

            var results = (typeof response.d) == 'string' ? eval('(' + response.d + ')') : response.d;
            PopulateTree(results);
        },

        error: function(xhr, status, error) {
            var msg = JSON.parse(xhr.responseText);
            alert(msg.Message);


        }
    });

$("#loading").ajaxStart(function() {
        alert("start");
        $(this).show();
    });

    $("#loading").ajaxStop(function() {
        alert("stop");
        $(this).hide();
        $("#st-tree-container").show();

    });

never fires alert “start” even though the gif is shown to rotate. AjaxStop gets triggered as expected.
Any ideas why?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-14T19:42:56+00:00Added an answer on May 14, 2026 at 7:42 pm

    It’s not getting triggered because your handler for .ajaxStart() isn’t registered until after the ajax request is already going (past when it would have been called). The .ajaxStop() is registered after as well, but before the request finishes, so when it comes back it is hooked up to run.

    To fix this, move this before your first $.ajax() call:

    $("#loading").ajaxStart(function() {
      $(this).show();
    }).ajaxStop(function() {
      $(this).hide();
      $("#st-tree-container").show();
    });
    

    UPDATE: Starting jQuery 1.9, AJAX events should be attached to document only.
    http://jquery.com/upgrade-guide/1.9/#ajax-events-should-be-attached-to-document

    $(document).ajaxStart(function() {
      $("#loading").show();
    });
    
    $(document).ajaxStop(function() {
      $("#loading").hide();
      $("#st-tree-container").show();
    });
    
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