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Home/ Questions/Q 7173291
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T15:47:40+00:00 2026-05-28T15:47:40+00:00

This code nums = [1..10].map (i) -> i*2 Runs Whereas this nums = [1..10].map(i)

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This code

nums = [1..10].map (i) -> i*2

Runs

Whereas this

nums = [1..10].map(i) -> i*2

is broken

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  1. Editorial Team
    Editorial Team
    2026-05-28T15:47:41+00:00Added an answer on May 28, 2026 at 3:47 pm

    The reason for this is that parentheses for a function call (invocation) are optional. I find this a constant confusion in my own code and have a general policy of always including parentheses to make it clear.

    In coffee script, if you leave out the parentheses it assumes that the argument list goes to the end of the line. Your first example coffee script is actually the same as this:

    nums = [1..10].map((i) -> i*2)
    

    where the first argument of the call to map is a function (i)->i*2

    If you remove the space between the map and the (i) then coffee script implies parentheses around the rest of the line. Your second example coffee script is actually the same as this:

    nums = [1..10].map(i)(-> i*2)
    

    Here you can see that map is being called with i as the only argument and then coffee script is expecting the map(i) call to return a function which is then being called passing ->i*2 or to be more explicit ()->i*2 as an argument.

    Given that coffee script is designed to remove the potential coding hazards of javascript, I think that it would have been much safer if they had not included this implied parenthesis.

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