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Home/ Questions/Q 7652367
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T11:45:02+00:00 2026-05-31T11:45:02+00:00

This code renders out a template ‘sites.htm’ in response to the POST request: def

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This code renders out a template ‘sites.htm’ in response to the POST request:

def post(self):
        acct = self.request.get('account')
        pw = self.request.get('password')

        que = db.Query(User)
        que = que.filter('account =', acct)
        que = que.filter('password =', pw)
        results = que.fetch(limit = 1)

        values = { }
        newval = dict(values)
        newval['path'] = self.request.path

        if len(results) > 0:
            arraySample = ['6','7','8','ninja']
            path = os.path.join(os.path.dirname(__file__), 'templates/sites.htm')
            self.response.out.write(template.render(path, {'arraySample':arraySample,'message':'Ninja IDE'}))

But I want my application to respond to that login attempt by redirecting to ‘sites.htm’ with the parameters of a dictionary.

I can’t just do self.redirect('sites.htm') because the elements from the dictionary won’t be shown.

Is there a way I can pass the dictionary as a url parameter to redirect() method?

Thanks in advance and I hope I was clear enough!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-31T11:45:03+00:00Added an answer on May 31, 2026 at 11:45 am

    put the dictionary in the query string. HTTP 101

    import urllib
    self.redirect("sites.htm?%s" % urllib.urlencode(dict(a="this and that", b="back and forth)))
    
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