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Home/ Questions/Q 7492871
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T16:38:14+00:00 2026-05-29T16:38:14+00:00

This code sample works as I would expect: v = QVariant(123456); qDebug() << v;

  • 0

This code sample works as I would expect:

v = QVariant("123456");
qDebug() << v; // QVariant(QString, "123456")
v.convert(QVariant::Int);
qDebug() << v; // QVariant(int, 123456)
v.convert(QVariant::String);
qDebug() << v; // QVariant(QString, "123456")

Where as this doesn’t:

v = QVariant("0xBEEF");
qDebug() << v; // QVariant(QString, "0xBEEF")
v.convert(QVariant::Int);
qDebug() << v; // QVariant(int, 0)
v.convert(QVariant::String);
qDebug() << v; // QVariant(QString, "")

Is there any simple way to make the QVariant class work with hexadecimal strings so the second example would work something like this:

v = QVariant("0xBEEF");
qDebug() << v; // QVariant(QString, "0xBEEF")
v.convert(QVariant::Int);
qDebug() << v; // QVariant(int, 48879)
v.convert(QVariant::String);
qDebug() << v; // QVariant(QString, "48879")
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-29T16:38:15+00:00Added an answer on May 29, 2026 at 4:38 pm

    When converting a qvariant to a numeric value you need to specify the base. Also make sure the value will fit in the int/long/longlong or then the conversion will fail for that reason instead.

    QVariant v = QVariant("0xDEADBEAF");
    bool test;
    qDebug() << v.toString().toLongLong(&test,16);
    qDebug() << test;
    

    will produce the correct output

    3735928495 
    true 
    

    while

    QVariant v = QVariant("0xDEADBEAF");
    bool test;
    qDebug() << v.toString().toInt(&test,16);
    qDebug() << test;
    

    will output

    0
    false
    
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