Question

This code show user’s process load (%cpu)

ps aux | awk 'NR!=1{print $1}' | sort | uniq | awk '{print "ps aux | grep "$1}' | awk '{printf $0; printf " | awk"; printf "{sum +="; print "$3}" }' | sed "s/{/ '{/g" | sed "s/3}/3} END {print \$1,sum}'/g" > 0.out

chmod 755 0.out

bash 0.out

This Code show same user in some OS(UBUNTU) example:
root 11.5
root 0
root 0
root 1.8
root 1.3
root 0
root 1.1

but show different user(uniq) on some OS example2:
root 11.5
daemon 0
syslog 0 ….

How can i write for example2 only.i want diff3rent user’s %cpu.

Answer 1

You can replace all that with:

ps ahx -o "%U %C" | awk '
  {cpu[$1] += $2} 
  END {for (user in cpu) {print user, cpu[user]}}
'