Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 587669
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 13, 20262026-05-13T15:14:12+00:00 2026-05-13T15:14:12+00:00

This code suffers from overflow because the type of intermediate results does not depend

  • 0

This code suffers from overflow because the type of intermediate results does not depend on the destination type:

vector< uint8_t > increments;
…
vector< uint32_t > increasing( increments.size() );
partial_sum( increments.begin(), increments.end(), increasing.begin() );

However, so does this (GCC 4.2):

partial_sum( increments.begin(), increments.end(), increasing.begin(),
             plus< uint32_t >() );

Shouldn’t plus< uint32_t > promote its operands and avoid the overflow?

Edit: I’m too SO-addicted. After a short break, I sat back down and checked the implementation. It does this:

  /* input_iterator::value_type */ __value = __binary_op(__value, *__first);
  *++__result = __value;

I don’t think that’s compliant, so I’ll check the latest version and maybe file a bug… and here we go: http://gcc.gnu.org/bugzilla/show_bug.cgi?id=42943

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-13T15:14:12+00:00Added an answer on May 13, 2026 at 3:14 pm

    According to http://www.open-std.org/jtc1/sc22/wg21/docs/lwg-active.html#539, partial_sum has been completely redefined since n3000 (the latest release):

    Effects: Let VT be InputIterator’s
    value type. For a nonempty range,
    initializes an accumulator acc of type
    VT with *first and performs *result =
    acc. For every iterator i in [first +
    1, last) in order, acc is then
    modified by acc = acc + *i or acc =
    binary_op(acc, *i) and is assigned to
    *(result + (i – first)).

    and

    The ‘widening’ behaviour can then be
    obtained by writing a custom proxy
    iterator, which is somewhat involved.

    I really can’t see the advantage of doing things this way. Reading the defect report, I don’t see any justification besides

    The intent of the algorithms is to perform their calculations using the
    type of the input iterator.

    Arrrgh.

    Edit: I went ahead and implemented a widening input iterator. Works as advertised.

    template< class Base, class Wider >
    struct widen_iter : iterator< input_iterator_tag, Wider > {
        Base b;
        widen_iter( Base const &inb = Base() ) : b( inb ) {}
        Wider operator*() const { return Wider( *b ); }
        Wider const *operator->() const { Wider t( *b ), *ta = &t; return ta; }
        widen_iter &operator++() { ++ b; return *this; }
        widen_iter operator++(int) { widen_iter t = *this; ++ b; return t; }
        bool operator==( widen_iter const &r ) const { return b == r.b; }
        bool operator!=( widen_iter const &r ) const { return b != r.b; }
    };
    template< class Wider, class Base >
    widen_iter< Base, Wider >
    widener( Base b ) { return widen_iter< Base, Wider >( b ); }
    

    Would be a lot shorter if there were a generic filter-by-functor input iterator.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Ask A Question

Stats

  • Questions 366k
  • Answers 366k
  • Best Answers 0
  • User 1
  • Popular
  • Answers
  • Editorial Team

    How to approach applying for a job at a company ...

    • 7 Answers
  • Editorial Team

    How to handle personal stress caused by utterly incompetent and ...

    • 5 Answers
  • Editorial Team

    What is a programmer’s life like?

    • 5 Answers
  • Editorial Team
    Editorial Team added an answer I have never seen screenLayout used that way. My guess… May 14, 2026 at 4:31 pm
  • Editorial Team
    Editorial Team added an answer When you pass a reference type (in your case, your… May 14, 2026 at 4:31 pm
  • Editorial Team
    Editorial Team added an answer Your colleague is completely wrong. He is mis-applying the fact… May 14, 2026 at 4:31 pm

Trending Tags

analytics british company computer developers django employee employer english facebook french google interview javascript language life php programmer programs salary

Top Members

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.