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Home/ Questions/Q 6056975
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Editorial Team
  • 0
Editorial Team
Asked: May 23, 20262026-05-23T08:26:13+00:00 2026-05-23T08:26:13+00:00

This code used to work but now it doesn’t and it’s only taking the

  • 0

This code used to work but now it doesn’t and it’s only taking the first value in the array…

var unavailableDates is an array that stops dates showing on the datepicker..

any ideas??

It’s not cycling through all dates in the array for some reason!?!?

var unavailableDates = ["4-7-2011","5-7-2011"];

function unavailable(date) {
    var dmy = date.getDate() + "-" + (date.getMonth() + 1) + "-" + date.getFullYear();
    if ($.inArray(dmy, unavailableDates) == 0) {
        return [false, "", "Unavailable"];
    } else {
        var day = date.getDay();
        return [(day != 0 && day != 2 && day != 3 && day != 4 && day != 6)];
    }
}

$(function(){

    $('#smh').datepicker({
        showOn: "both",
        buttonImage: "images/calendar.gif",
        buttonImageOnly: true,
        beforeShowDay: unavailable,
        minDate: -0,
        dateFormat: "dd/mm/yy",
        onSelect: function(e) {
        e = e.split('/')[1] + '/' + e.split('/')[0] + '/' + e.split('/')[2];
        var date = new Date(e);
        var day = date.getDay(); // 0 = sunday etc...        
        if (day === 1) {
            $("#check2").hide();
            $("#text").hide();
            $("#check1").show();

        } else if (day === 5) {
            $("#check1").hide();
            $("#text").hide();
            $("#check2").show();

        } 
        $("#bdate").html(this.value);
    } 
    })
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T08:26:14+00:00Added an answer on May 23, 2026 at 8:26 am

    In jQuery the $.inArray(elem, array) method returns -1, and not 0, when elem is not found in array.

    So I think you should use:

    if ($.inArray(dmy
    , unavailableDates) == -1)

    instead of:

    if ($.inArray(dmy, unavailableDates) == 0)

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