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Home/ Questions/Q 597771
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T16:18:59+00:00 2026-05-13T16:18:59+00:00

This code will throw Concurrent Modification Exception if the list is modified in doSomething().

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This code will throw Concurrent Modification Exception if the list is modified in doSomething(). Is it possible to avoid it by enclosing the code in some synchronized block?

List l = Collections.synchronizedList(new ArrayList());

// normal iteration -- can throw ConcurrentModificationException
// may require external synchronization
for (Iterator i=list.iterator(); i.hasNext(); ) {
  doSomething(i.next());
}
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  1. Editorial Team
    Editorial Team
    2026-05-13T16:18:59+00:00Added an answer on May 13, 2026 at 4:18 pm
    • if you are removing an item from the list, you can do it by calling iterator.remove() instead of list.remove(iterator.next())

    • if you are adding an item – well, create a copy of the iterated list and add it there

    • if the code snippet above is part of the same method, then you don’t need a synchronized list or synchronized blocks – no other thread can access the local list.

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